2) 2Al+3S=Al2S3
2Al+2H2O+2NaOH=2NaAlO2+3H2
1) 2Al+3Cl2=2AlCl3
AlCl3+3NaOH=Al(OH)3+3NaCl
Al³⁺ + 3Cl⁻ + 3Na⁺ + 3OH⁻ = Al(OH)3 + 3Na⁺ + 3Cl⁻
Al³⁺ + 3OH⁻ =Al(OH)₃
2Al(OH)3=Al2O3+3H2O
Al2O3+6HCl=2AlCl3+3H2O
задача
хг 5г
AlCl3+3NaOH=Al(OH)3+3NaCl
133,5 120г
м в-ва = м р-ра * ω/100%= 50г*10%/100% = 5г
х= 133,5*5/120=5,56г m (AlCl3)