sin2x-(корень3)cos2x=0 помогите)

Question

sin2x-(корень3)cos2x=0 помогите)

Answer 1

Cos2x ≠ 0, 

SIn2x = √3Cos2x

tg2x = √3

2x = arctg(√3)+πk, k∈Z

x = π/6 + πk/2