Итак приступим № 1)=(sinA/cosA)-sinA)/(sinA/cosA)+sinA)=((sinA-sinAcosA)cosa)/(cosA(sinA+sinA cosA))=(sinA(1-cosA))/(sinA(1+cosA))=(1-cosA)/ (1+cosA)
2)(cos²bsin²b-cos²b)/sin²b :(sin²bcos²b-sin²b)/cos²b=cos²b(sin²b-1)/sin²b : sin²b(cos²b-1)/cos²b=cos²b*(-cos²b)/sin²b : sin²b(-sin²b)cos²b= -cos4b/sin²b : -sin^4b/cos²b=cos^4b/sin²b*cos²b/sin^4b=cos^6b/sin^6b=ctg^6b
(tgb+ctgb)(tg²b-tgbctgb+ctg²b)/(tg²b-2tgbctgb+ctg²b-1)=
(tgb+ctgb)(tg²b-1+ctg²b)/(tg²b-2+ctg²b+1)=(tgb+ctgb)(tg²b-1+ctg²b)/(tg²b+ctg²b-1)=
(tgb+ctgb)=(sinbsinb+cosbcosb)/sinb*cosb=(sin²b+cos²b)/1/2sin2b=2/sin2b
4)4)3sin0+2cos0=3x0+2*1 = 0+2= 2 ...так как sin0=0, a cos0=1