1/y +2 +1/y + 2-2y=8/y3-4y
1/y+2+1/y+2+(-2)y = - (2*(y2-2y-1))/2
(8/y3)-4y=(4*(y4-2))/y3
-(2*(y2-2y-1))/2 = (4*(y4-2))/y3
-2y+(2/y)+4 = (8/y3)-4y
2y+(2/y)-(8/y3)+4=0
(2(y4+2y3+y2-4))/y=0
1/y3=0
y4+2y3+y2-4=0
y2+y+2=0
d=b2-4ac=1^2-4*(1*2)=-7
d<0</p>
y=-2, y=1