x^3-3x^2-3x+1=0
x^3-3x^2-3x+1 / x+1
x^3+x^2 x^2-4x+1
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-4x^2-3x
-4x^2-4x
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x+1
x+1
------
0
x^3-3x^2-3x+1=0
(x+1)(x^2-4x+1)=0
x+1=0 x^2-4x+1=0
x=-1 D=12
x1=(4+2sqrt{3})/2=2+sqrt{3}
x2=(4-2sqrt{3})/2=2-sqrt{3}
Ответ:-1; 2+sqrt{3};2-sqrt{3}