x+2<5x-2(x-3) 4(x+8)-7(x-1)<12

Question

x+2<5x-2(x-3)</p>

4(x+8)-7(x-1)<12</p>

Answer 1

x+2<5x-2(x-3)                       4(x+8)-7(x-1)<12</p>

x+2<5x-2x+6                         4x+32-7x+7<12</p>

x-3x<6-2                               -3x<-27</p>

-2x<4                                    x>9

x>-2                                      (9;+бесконечность)

(-2; +бесконечность)

 

 

Answer 2

x+2<5x-2(x-3)</p>

х-5х+2х<6-2</p>

-2х<4</p>

х>-2

х∈(-2;+∞)

4(x+8)-7(x-1)<12</p>

4х+32-7х+7<12</p>

-3х<12-32-7</p>

3х<27</p>

х>9

х∈(9;+∞)