1)Цинкмассой6,5кг обработалали 120кг 10% р-ра серной кислоты. определить объем...

$1. \ n(Zn) = \frac{m}{Mr} = \frac{6500}{65} = 100\ mol\\ \\ 2. \ n(H_{2}SO_{4}) = \frac{m_{r-ra}*w}{Mr} = \frac{12000}{98} = 122.45\ mol\\ \\ 100=122.45=======x=\\ Zn + H_{2}SO_{4} = ZnSO_{4} + H_{2}\\ =1==1====1===1==\\ \\ x \ mol = 100\ mol\\ 3. V(H_{2}) = n_{chist}*Vm = n*0.95*22.4 = 2.128 *10^3\ dm^3$

Ответ: 2128 дм^3

$1. \ n(Mg) = 0.5\ mol\\ 2. \ n(SiO_{2}) = 0.2\ mol\\ \\ =0.5=0.2==x=====\\ 2Mg + SiO_{2} = Si + 2MgO\\ =2==1===1==2==\\ \\ 3. \ n(Si) = x = 0.2 \ mol\\ \\ ====0.2==y(0.4)==========\\ H_{2}O + Si + 2NaOH = Na_{2}SiO_{3}+2H_{2}\\ ====1===2=============\\ \\ 4. \ n(NaOH) = y\ mol = 0.4\ mol\\ \\ 5. \ m(NaOH) = \frac{n*Mr}{w} = 50\ g.\\ \\ 6. V = m/p = 50/1.35 = 37 ml$

Ответ: 37 мл