1)-0.12:(1 4/5)2)0.1:(-1/12)=3)-4/9:1,6помогите решить

Решите задачу:

$1)-0,12:\left(1\frac45\right)=-\frac{12}{100}:\frac95=-\frac{12}{100}\cdot\frac59=-\frac{4\cdot1}{20\cdot3}=\\=-\frac4{60}=-\frac1{15}\\ 2)\;0,1:\left(-\frac1{12}\right)=-\frac1{10}\cdot12=-\frac{10}{12}=-\frac56\\ 3)\;-\frac49:1,6=-\frac49:\frac{16}{10}=-\frac49\cdot\frac{10}{16}=-\frac19\cdot\frac{10}4=-\frac{1\cdot5}{9\cdot2}=-\frac5{18}$