Решите уравнение : log1/7 (x+4)+log1/7 (8-x)=log 1/7 (32-5x)

Question

Решите уравнение : log1/7 (x+4)+log1/7 (8-x)=log 1/7 (32-5x)

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Answer 1

log1/7 (x+4)+log1/7 (8-x)=log 1/7 (32-5x)
x<8 x>-4 x<32/5<br>(x+4)(8-x)=32-5x
8x-x²+32-4x=32-5x
x²-9x=0
x(x-9)=0
x=0
x=9 не проходит по ОДЗ

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