Если f(x)=(1-2x)(2x+1), то найдите f''(1)
F(x)=1-4x^ f'(x)=-8x f''(x)=-8 f''(1)=-8
(1-2х)' (2х+1) + (2х+1)' (1-2х) = -2(2х+1)+2(1-2х)=-4х-2+2-4х= - 8х -8*1= -8