Дана функция f(x)= 3x+4 найдите а)f(2) б) f(x-1) в)f(x^2)
F(2)=3*2+4=10 f(X-1)=3*(x-1)+4=3x -3+4=3x +1 f(x^2)=3x^2 +4
А) f ( 2 ) = 6 + 4 = 10 б) f ( X - 1 ) = 3 * ( X - 1 ) + 4 = 3X - 3 + 4 = 3X + 1 B) f ( X^2 ) = 3 *( 3X + 4)^2 + 4 = 3 * ( 9X^2 + 24X + 16) + 4 = = 27X^2 + 72X + 52