Решите пожалуйста)145 номер)срочн

А) $9 x^{2} -1-(3 x-2) ^{2} =0$
$9 x^{2} -1-9 x^{2} -12 x+4=0$
$-12 x+3=0$
$-12 x=-3$
$x= \frac{1}{4}$
б) $(2 x-3) ^{2} -2 x(4+2 x)=11$
$4 x^{2} -12 x+9-8 x-4 x^{2} -11=0$
$-20 x-2=0$
$-20 x=2$
$x=- \frac{1}{10}$
в) $x+(5 x+2) ^{2} =25(1+ x^{2} )$
$x+25 x^{2} +20 x+4=25+25 x^{2}$
$x+25 x^{2} +20 x+4-25-25 x^{2} =0$
$21 x-21=0$
$21 x=21$
$x=1$
г) $(4 x-3)(3+4 x)-2 x(8 x-1)=0$
$12 x+16 x^{2} -9-12 x-16 x^{2} +2 x=0$
$2 x-9=0$
$2 x=9$
$x=4,5$