Cu(OH)2+NaOH=Fe+CuSO4=BaO+KOH=Zn+HCL=

Question

Cu(OH)2+NaOH=
Fe+CuSO4=
BaO+KOH=
Zn+HCL=

Answer 1

Cu(OH)₂ + 2NaOH (горячий, конц. р-р) —(t°)→ Na₂[Cu(OH)₄]. Fe + CuSO₄ → Cu↓ + FeSO₄. BaO + KOH ↛. Zn + 2HCl → ZnCl₂ + H₂↑.

Answer 2

= Сu(OH)₂ + NaOH
= Fe₂SO₄ + Cu
= BaOH + K₂O
= ZnCl + H₂

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