Решите номер 1285! Прошу вас!!!

Question 1

Question 2

Решите задачу:

$4- \frac{1}{3- \frac{1}{2- \frac{1}{2} } } =4- \frac{1}{3- \frac{1}{ 1\frac{1}{2} } }=4- \frac{1}{3- \frac{2}{3} } }=4- \frac{1}{2 \frac{1}{3} } =4- \frac{3}{7}=3 \frac{4}{7}$

$7- \frac{1}{5- \frac{1}{1- \frac{1}{2} } }= 7- \frac{1}{5- \frac{1}{ \frac{1}{2} } }=7- \frac{1}{5-2 } }=7- \frac{1}{3} =6 \frac{2}{3}$

$6- \frac{2}{5- \frac{2}{4- \frac{2}{3} } }= 6- \frac{2}{5- \frac{2}{3 \frac{1}{3} } }=6- \frac{2}{5- \frac{2}{ \frac{10}{3} } }=6- \frac{2}{5- \frac{6}{ {10} } }=6- \frac{2}{4 \frac{4}{ {10} } }=6- \frac{2}{ \frac{44}{ {10} } }=6-\frac{20}{44} =5 \frac{24}{44}=5 \frac{6}{11}$

$\frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{4- \frac{4}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{3 \frac{1}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{ \frac{16}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{40}{ 16} } } }=\frac{3}{4}+ \frac{7}{6- \frac{3}{ \frac{120}{ 16} } }=\frac{3}{4}+ \frac{7}{6- \frac{48}{120} } }=\frac{3}{4}+ \frac{7}{5 \frac{72}{120} } }=\frac{3}{4}+ \frac{7}{\frac{672}{120} } }=\frac{3}{4}+ \frac{840}{672} } }= \frac{3}{4}+ 1 \frac{168}{672} =\frac{3}{4}+ 1 \frac{1}{4}=2$

Question 3

[tex] \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{4- \frac{4}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{3 \frac{1}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{8}{ \frac{16}{5} } } }= \frac{3}{4}+ \frac{7}{6- \frac{3}{5+ \frac{40}{ 16} } } }=\frac{3}{4}+ \frac{7}{6- \frac{3}{ \frac{120}{ 16} } }=\frac{3}{4}+ \frac{7}{6- \frac{48}{120} } }=\frac{3}{4}+ \frac{7}{5 \frac{72}{120} } }=\frac{3}{4}+ \frac{7}{\frac{672}{120} } }=\frac{3}{4}+ \frac{840}{672} } }= \frac{3}{4}+ 1 \