Помогите, пожалуйста

Решите задачу:

$1)(1- \frac{1}{2} ):( \frac{1}{2} - \frac{1}{3} )= \frac{1}{2} :( \frac{3}{6} - \frac{2}{6} )= \frac{1}{2} : \frac{1}{6} = \frac{6}{2} =3 \\ \\$

$2)( \frac{3}{4} + \frac{1}{6} )*3+( \frac{5}{6} - \frac{1}{2} ): \frac{2}{9} =4.25 \\ \\ 1) \frac{3}{4} + \frac{1}{6} = \frac{3*3}{4*3} + \frac{1*2}{6*2} = \frac{9}{12} + \frac{2}{12} = \frac{11}{12} \\ \\ 2) \frac{11}{12} *3= \frac{11*3}{12} = \frac{11}{4} \\ \\ 3) \frac{5}{6} - \frac{1}{2} = \frac{5}{6} - \frac{1*3}{2*3} = \frac{5}{6} - \frac{3}{6} = \frac{2}{6} = \frac{1}{3} \\ \\ 4) \frac{1}{3} : \frac{2}{9} = \frac{1*9}{3*2} = \frac{3}{2} \\ \\$

$5) \frac{11}{4} + \frac{3}{2} = \frac{11}{4} + \frac{3*2}{2*2} = \frac{11}{4} + \frac{6}{4} = \frac{17}{4} =4 \frac{1}{4} =4 \frac{1*25}{4*25} = \\ \\ =4 \frac{25}{100} =4.25$