9^(x+1) + 3 >= 28 * 3^x
9^(x+1) + 3 >= 28 * 3^x 3^x=t 9t²-28t+3≥0 D=784-108=676 t12=(28+-26)/18=1/9 3 9(t-1/9)(t-3)≥0 ======1/9==========3======= ++++++ ------------- +++++ 3^x<=1/9<br>x<=-2<br>3^x>=3 x>=1 x=(-oo -2]U[1 +oo)
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