(4 целых 1/6у +11 целых 1/4)* 4/15= 2/3у+ 5 целых 2/3

Решите задачу:

$(4\frac{1}{6}y + 11\frac{1}{4}) * \frac{4}{15} = \frac{2}{3}y + 5\frac{2}{3}\\ \\ (\frac{25}{6}y + \frac{45}{4}) * \frac{4}{15}=\frac{2}{3}y+\frac{17}{3}\\ \\ \frac{10}{9}y + 3 = \frac{2}{3}y + \frac{17}{3}\\ \\ \frac{10}{9}y + 3 - \frac{2}{3}y - \frac{17}{3}=0\\ \\ \frac{4}{9}y - \frac{8}{3} = 0\\ \\ \frac{4}{9}y = \frac{8}{3}\\ \\ y = \frac{8}{3} * \frac{9}{4}\\ \\ y = 6$