Решите уравнение плииз

$1) x^3 + 4x^2 = 9x + 36 \\ x^3 + 4x^2 - 9x -36 = 0 \\ x(x^2 + 4x - 9 - 36) = 0 \\ x_1 = 0 \\ x^2 + 4x -9-36 = 0 \\ x^2 + 4x - 45 = 0 \\ D = 4^2 - 4 * (-45) = 16 + 180 = 196 \\ x_2,_3 = \frac{-4б \sqrt{D} }{2} = \frac{-4б \sqrt{196} }{2} = \frac{-4б 14 }{2} \\ x_2 = 5\\x_3 = -9$
Ответ: $-9;0;5$

$2) x^3 = x^2 + 6x\\x^2 + 6x - x^3 = 0\\ x(x + 6 - x^2) = 0\\ x_1 = 0\\ x + 6 - x^2 = 0\\ x^2 - x - 6 = 0\\D = (-1)^2 - 4 * (-6) = 1 + 24 = 25\\ x_2,_3 = \frac{1 б \sqrt{D} }{2} = \frac{1 б \sqrt{25} }{2} = \frac{1 б 5 }{2} \\ x_2 = 3\\x_3= - 2$
Ответ: $-2;0;3$