Найдите производную функции

А) $f'(x)=x^2+2x+2$

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б) $y'(x)=- \frac{6}{x^4} -1$

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в) $g'(x)=4cosx \\ g'(- \frac{2 \pi }{3} )=g'(\frac{2 \pi }{3} )=4cos(\frac{2 \pi }{3} )=-2$

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г) $h'(x)= \frac{-3x(x+2)-(2-3x)}{(x+2)^2} = \frac{-3x^2-6x-2+3x}{(x+2)^2} =- \frac{3x^2+3x+2}{(x+2)^2} \\ \\ h'(-1)= -\frac{3-3+2}{1} =-2$