1)3*4=12
2)13*2=26
3)3^log(3)49=49
4)log(0,2)(0,2)^-3=-3
5)log(25)(25^-1/2=-1/2
6)log(6)234/6,5=log(6)36=2
7)log(25)25+log(0,2)^-4=1-4=-3
8)log(0,3)10/3=-1
9)log(2)4=2
10)log(9)2 : log(9)2/2=log(9)2 * 2/log(9)2=2
11)log(4)13 * log(4)16/log(4)13=log(4)16=2
12)2^log(13)507-log(13)3=2^log(13)169=2²=4
13)(1-( log(6)6+log(6)8)/log(6)8)(1-(log(6)6+log(6)8)=
(1-(1+log(6)8/log(6)8)*(1-1-log96)8)=(log(6)8-1-log(6)8)/log(6)8 *(-log(6)8=
-1*(-1)=1
14)50*log(10)10^0,2=50*0,2=10
15)log(![\sqrt[5]{10}](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B10%7D+++ "\sqrt[5]{10}")
)(()^5=5
16)((log(2)13+log(2)4)/2+log(2)13=1
(2)-это основание у логарифма