Решите систему уравнения:y-2x=22x-4y=8

$\left \{ {{y-2x=2} \atop {2x-4y=8}} \right.$
$\left \{ {{y=2+2x} \atop {2x-4(2+2x)=8}} \right.$
$\left \{ {{y=2+2x} \atop {2x-8-8x=8}} \right.$
$\left \{ {{y=2+2x} \atop {2x-8x=8+8}} \right.$
$\left \{ {{y=2+2x} \atop {-6x=18}} \right.$
$\left \{ {{y=2+2x} \atop {x=-3}} \right.$
$\left \{ {{y=2+2*(-3)} \atop {x=-3}} \right.$
$\left \{ {{y=2+(-6)} \atop {x=-3}} \right.$
$\left \{ {{y=2-6} \atop {x=-3}} \right.$
$\left \{ {{y=-4} \atop {x=-3}} \right.$
Ответ: y=-4; x=-3.