дана функция y=f(x),где f(x)= -3x+2. Найдите:а) f(0),f(-3),f(2/3),f(-1/3)

Question

дана функция y=f(x),где f(x)= -3x+2. Найдите:а) f(0),f(-3),f(2/3),f(-1/3)

Answer 1

f(0)=-3*0+2=2

f(2/3)=-3*(2/3)+2=0

f(-1/3)=-3*(-1/3)+2=3

Answer 2

f(0)=-3*0+2=2

f(-3)=-3*(-3)+2=9+2=11

f(2/3)=-3*2/3+2=0

f(-1/3)=-3*(-1/3)+2=3