7x^2-43x-42=0 помогите
7x² - 43x - 42 = 0 D = b² - 4ac = (-43)² - 4 · 7 · (-42) = 1849 + 1176 = 3025 x₁ = (43 - 55) / 14 = -12/14 = -6/7 x₂ = (43 + 55) / 14 = 98/14 = 7 Ответ: x₁ = -6/7; x₂ = 7
7^2-43x-42=0 D=b^2-4ac=-1849-4*7*42=-1849-1176=3025: 3025=55 x1=43+55/2*7=98/14=7 x2=43-55/2*7=-12/14=-6/7