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Решите задачу:

$2 \frac{3}{4}/((4 \frac{5}{12}-1 \frac{11}{14})*4 \frac{2}{3}+(3 \frac{2}{9}-1 \frac{5}{6})* \frac{18}{25})= \frac{99}{486}$

$4 \frac{5}{12}-1 \frac{11}{14}= 4 \frac{35}{84}-1 \frac{66}{84}=3 \frac{119}{84}-1 \frac{66}{84}=2 \frac{53}{84}$

$3 \frac{2}{9}-1 \frac{5}{6}= 3 \frac{4}{18}-1 \frac{15}{18}= 2 \frac{22}{18}-1 \frac{15}{18}=1 \frac{7}{18}$

$2 \frac{53}{84}*4 \frac{2}{3}=\frac{221*14}{84*3}= \frac{221}{18}=12 \frac{5}{18}$

$1 \frac{7}{18}* \frac{18}{25}= \frac{25*18}{18*25}=1$

$12 \frac{5}{18}+1=13 \frac{5}{18}$

$2 \frac{3}{4}/ 13 \frac{5}{18}= \frac{11*18}{4*239}= \frac{99}{486}$