Решите задачу:
(x√3+√2)²+(x√3-√2)²-10x=0 3x²+2x√6+2+3x²-2x√6+2-10x=0 6x²-10x+4=0 D=100-96=4 x1=(10-2)/12=8/12=2/3 x2=(10+2)/12=1