Sinx*cosx+cos (в квадрате) x=0
Sinx * cosx + cos^2x = 0 cosx * ( sinx + cosx ) = 0 # 1 cosx = 0 ==> x = pi/2 + pik, k ∈ Z # 2 sinx + cosx = 0 I : cosx ≠ 0 tgx + 1 = 0 tgx = - 1 x = - arctg (1) + pik x = - pi/4 + pik, k ∈ Z Ответ: x = pi/2 + pik, k ∈ Z x = - pi/4 + pik, k ∈ Z