Помогите решить уравнение 2 cos^2x+14 cosx=3 sin^2x
2cos^2(x) + 14cosX - 3sin^2(x) = 0 ==> 5cos^2(x) + 14cosX - 3 =0 ==> cosX = -3 or cosX = 0.2 ==> cosX = 0.2 ==> X = +-arccos(0.2) + 2pi*n