А) -√3-2sin3x<0б) ctg (+x)>√3

Question

А) -√3-2sin3x<0<br>
б) ctg (+x)>√3

Answer 1

Sin3x>-√3/2
-π/3+2πn<3x<4π/3+2πn<br>-π/9+2πn/3x∈(-π/9+2πn/3;4π/9+2πn/3)

πn<π/2+x<π/6+πn<br>-π/2+πn-π/2+πnx∈(-π/2+πn;-π/3+πn)