(2х+7)(3х-1)-(5х-1)(х+3)=(х+1)^2
6x^2 + 21x - 2x - 7 - 5x^2 + x - 15x + 3 = x^2 + 2x +1 x^2 + 5x - 4 -x^2 - 2x -1 = 0 3x = 5 x = 1 2/3
Решите задачу: