Как такое решить? 2^x^2-40x+300 = 1
2 ^ ( X^2 - 40X + 300 ) = 1 2 ^ ( X^2 - 40X + 300) = 2 ^ 0 -------------------------------- X^2 - 40X + 300 = 0 D = 1600 - 1200 = 400 √ D = 20 X1 = ( 40 + 20 ) : 2 = 30 X2 = ( 40 - 20) : 2 = 10