Помогите срочно 7^log7^2-log3^9

Question

Помогите срочно
7^log7^2-log3^9

Answer 1

3^(2-LOG3^5)+(1\3)^LOG3 5= 3^2 / 3^(log(3)5)+1/(3^log(3)5)=9/5+1/5=2 9^(3-log(3)54)+7^(-log(7)2)= 9^3/ (3^log(3)54)^2+7^(-log(7)2) =1/4+1/7^(log(7)2)=1/4+1/2=3/4