Решите систему уравнений {(5x+3)²=8y,(3x+5)²=8y.

Решите задачу:

$\left \{ {{(5x+3)^{2}=8y} \atop {(3x+5)^{2}=8y}} \right. \left \{ {{(5x+3)^{2}=(3x+5)^{2}} \atop {8y=9x^{2}+30x+25}} \right. \left \{ {{x=1} \atop {8y=64}} \right. \left \{ {{x=1} \atop {y=8}} \right.$
$(5x+3)^{2}=(3x+5)^{2}$
$25x^{2}+30x+9=9x^{2}+30x+25$
$25x^{2}-9x^{2}=25-9$
$16x^{2}=16$
$x^{2}=16:16$
$x^{2}=1$
$x=1$