Помогите с системой уравнений,пожалуйста

Решите задачу:

$\left \{ {{\frac{x+y}{2}-\frac{x-y}{3}=\frac{7}{6}} \atop {\frac{x-y}{4}+\frac{x+y}{3}=\frac{5}{4}}} \right. \left \{ {{3(x+y)-2(x-y)=7} \atop {3(x-y)+4(x+y)=15} \right. \left \{ {{3x+3y-2x+2y=7} \atop {3x-3y+4x+4y=15} \right. \left \{ {{x+5y=7} \atop {7x+y=15} \right. \\ \left \{ {{x=7-5y} \atop {7(7-5y)+y=15} \right. \left \{ {{x=7-5y} \atop {49-35y+y=15} \right. \left \{ {{x=7-5y} \atop {49-34y=15} \right. \left \{ {{x=7-5y} \atop {34y=34} \right.\left \{ {{x=7-5y} \atop {y=1} \right. \\$
$\left \{ {{x=7-5*1} \atop {y=1} \right. \left \{ {{x=2} \atop {y=1} \right.$