Уравнения. x²-5x+6=0 x²-7x+10=0 y²+8y+16=0 y²-10y+25=0

Решите задачу:

$1) x^{2} -5x+6=0 \\ D=25-24=1 \\ \sqrt{D} =1 \\ x_{1} = \frac{5+1}{2} = \frac{6}{2} =3 \\ x_{2} = \frac{5-1}{2} = \frac{4}{2} =2 \\ \\ 2) x^{2} -7x+10=0 \\ D=49-40=9 \\ \sqrt{D} =3 \\ x_{1} = \frac{7+3}{2} = \frac{10}{2} =5 \\ x_{2} = \frac{7-3}{2} = \frac{4}{2} =2 \\ \\$

$3)y^{2} +8y+16=0 \\ D=64-64=0 \\ y _{0} = \frac{-8}{2} =-4 \\ \\ 4)y^{2} -10y+25=0 \\ D=100-100=0 \\ y_{0} = \frac{10}{2} =5$