3/logab - logba^2 - log3а/log3b

Question

3/logab - logba^2 - log3а/log3b

---

Answer 1

Log(a)a³/log(a)b  -log(b)a² -log(b)a=log(b)a³ -log(b)a² -log(b)a=
=3log(b)a-2log(b)a-log(b)a=0