Вычислить: (6 5/6 - 4 7/8)*3 3/4(19/20-13/18)*28 4/41

Решите задачу:

$(6\frac{5}{6}-4\frac{7}{8})*3\frac{3}{4}*(\frac{19}{20}-\frac{13}{18})*28\frac{4}{41} \\ \\ 1)6\frac{5}{6}-4\frac{7}{8}=\frac{41}{6}-\frac{39}{8}=\frac{41*8-39*6}{48}=\frac{328-234}{48}=\frac{94}{48}=\frac{47}{24}=1\frac{23}{24} \\ \\ 2)\frac{19}{20}-\frac{13}{18}=\frac{19*9-13*10}{180}=\frac{171-130}{180}=\frac{41}{180} \\ \\ 3)1\frac{23}{24}*3\frac{3}{4}*\frac{41}{180}*28\frac{4}{41}=\frac{47}{24}*\frac{15}{4}*\frac{41}{180}*\frac{1152}{41}=47$