в) (2-3х)^2+(1+4x)^2=(5x-1)(5x+1)-4x

Question

в) (2-3х)^2+(1+4x)^2=(5x-1)(5x+1)-4x

Answer 1

(2-3х)"+(1+4х)"=(5х-1)(5х+1)-4х  ( " )-в квадрате
4-12х+9х"+1+8х+16х"=25х"-1-4х
9х"+16х"-25х"-12х+8х+4х+4+1+1=6