![image](https://tex.z-dn.net/?f=1%29%5C%3B+%5Cfrac%7Bx%5E2-7x%2B12%7D%7Bx%2B2%7D%3C0%2C%5C%3B+%5C%3B+%5Cfrac%7B%28x-3%29%28x-4%29%7D%7Bx%2B2%7D%3C0%5C%5C%5C%5C----%28-2%29%2B%2B%2B%283%29---%284%29%2B%2B%2B%2B%5C%5C%5C%5Cx%5Cin+%28-%5Cinfty%2C-2%29U%283%2C4%29%5C%5C%5C%5C2%29%5C%3B+%5Cfrac%7Bx%5E3%2B8%7D%7Bx%5E2-25%7D+%5Cgeq+0%2C%5C%3B+%5Cfrac%7B%28x%2B2%29%28x%5E2-2x%2B4%29%7D%7B%28x-5%29%28x%2B5%29%7D+%5Cgeq+0%2C%5C%5C%5C%5Cx%5E2-2x%2B4%3E0%5C%3B+pri%5C%3B+x%5Cin+R%5C%5C%5C%5C---%28-5%29%2B%2B%2B%5B-2%5D---%285%29%2B%2B%2B%5C%5C%5C%5Cx%5Cin+%28-5%2C-2%5DU%285%2C%2B%5Cinfty%29)
0\; pri\; x\in R\\\\---(-5)+++[-2]---(5)+++\\\\x\in (-5,-2]U(5,+\infty)" alt="1)\; \frac{x^2-7x+12}{x+2}<0,\; \; \frac{(x-3)(x-4)}{x+2}<0\\\\----(-2)+++(3)---(4)++++\\\\x\in (-\infty,-2)U(3,4)\\\\2)\; \frac{x^3+8}{x^2-25} \geq 0,\; \frac{(x+2)(x^2-2x+4)}{(x-5)(x+5)} \geq 0,\\\\x^2-2x+4>0\; pri\; x\in R\\\\---(-5)+++[-2]---(5)+++\\\\x\in (-5,-2]U(5,+\infty)" align="absmiddle" class="latex-formula">