x^{2} -у^{2} =8,х-у=2 решите пожалуйста систему

Решите задачу:

$\left \{ {{x^2-y^2=8} \atop {x-y=2}} \right. \\ \left \{ {{(x-y)(x+y)=8} \atop {x-y=2}} \right. \\ \left \{ {{2(x+y)=8} \atop {x-y=2}} \right. \\ \left \{ {{x+y=4} \atop {x-y=2}} \right. \\ \left \{ {{x=4-y} \atop {4-y-y=2}} \right. \\ \left \{ {{x=4-y} \atop {2y=4-2}} \right. \\ \left \{ {{y=1} \atop {x=4-y=4-1=3}} \right.$