4 / ( √ 3 - X ) - ( √ 3 - X ) < 2 <br>------------
√ 3 - X = A
A > 0
3 - X ≠ 0 ; X ≠ 3
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( 4 / A ) - A < 2
( 4 - A^2 ) / A < 2
4 - A^2 < 2A
- A^2 - 2A + 4 < 0
A^2 + 2A - 4 < 0
D = 4 - 16 = 20 ; √ D = 2 √ 5
A1 = ( - 2 + 2 √ 5 ) : 2 = ( - 1 + √ 5 ) ; > 0
A2 = ( - 1 - √ 5 ) ; < 0
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√ ( 3 - X ) = - 1 + √ 5
( √ 3 - X)^2 = ( √ 5 - 1 )^2
3 - X = 5 - 2√ 5 + 1
X = 3 - 5 + 2√ 5 - 1 = ( - 6 + 2 √ 5 )
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X ∈ ( - бесконечность ; - 6 + 2√ 5 )