1. n(NH3)=1.7/17=0.1 моль
V(NH3)=0.1*22.4=2.24 л
2.m(Na)=2*23=46
m(Cr)=52
m(O)=4*16=64
m(Na2CrO4)=46+52+64=162
w(Na)=46/162*100%=28.4%
w(Cr)=52/162*100%=32.1%
w(O)=64/162*100%=39.5%
3.M(газа)=22*4=88 г/моль
4.n(KClO3)=49/122.5=0.4 моль
n(O2)=0.4*3/2=0.6 моль
V(O2)=0.6*22.4=13.44 л