(x+5)2+(x-10)=2X2 помогите!!!!!!!!!!!!!!!!!!!
(x+5)^2+(x-10)=2x^2 x^2+10x+25+x-10=2x^2 -x^2+11x+15=0 x^2-11x-15=0 д=121+4*15=181 x1.2=(11 -+ √181) / 2 =======================
не павильно
(x+5)^2+(x-10)=2x^2 x^2+10x+25+x-10=2x^2 -x2 + 10x + 35 = 0 D = b2 - 4ac = 102 - 4·(-1)·35 = 100 + 140 = 240 x1=-10 - √240/2·(-1) ≈ 12.7 x2=-10 +√240/2·(-1) ≈ -2.74