Помогите мне

Введём обозначения:

$t=\frac{2}{2x-y},\; v=\frac{1}{x-2y}\; \; \to \\\\ \left \{ {{t+3v=\frac{1}{2}} \atop {t-v=\frac{1}{18}}} \right. \; \left \{ {{t=\frac{1}{2}-3v} \atop {t=v+\frac{1}{18}}} \right. \; \; \to \; \; \frac{1}{2}-3v=v+\frac{1}{18}\\\\4v=\frac{1}{2}-\frac{1}{18}=\frac{8}{18}=\frac{4}{9}\\\\v=\frac{1}{9},\; \; \to \; \frac{1}{x-2y}=\frac{1}{9}\; \to \; x-2y=9\\\\t-\frac{1}{9}=\frac{1}{18} ,\; \; t=\frac{1}{18}+\frac{1}{9}=\frac{3}{18}=\frac{1}{6}\; \to \frac{2}{2x-y}=\frac{1}{6}\; \to \; 2x-y=12$

$\left \{ {{x-2y=9} \atop {2x-y=12}} \right. \; \left \{ {{x-2y=9} \atop {3y=-6}} \right. \; \left \{ {{x=13} \atop {y=-2}} \right.$