Решите систему уравнений: {4(x-2)-3(y+3)=1 {3(x+2)-2(x-y)=5

Решите задачу:

$\left \{ {{4(x-2)-3(y+3)=1} \atop {3(x+2)-2(x-y)=5}} \right. \left \{ {{4x-8-3y-9=1} \atop {3x+6-2x+2y=5}} \right. \left \{ {{4x-3y-17=1} \atop {x+2y+6=5}} \right. \left \{ {{4x-3y=1+17} \atop {x+2y=5-6}} \right. \\ \left \{ {{4x-3y=18} \atop {x+2y=-1}/*(-4)}\right. \left \{ {{4x-3y=18} \atop {-4x-8y=4}} \right. \\ -11y=22 \\ y=-2 \\ 4x+6=18 \\ 4x=12 \\ x=3 \\ \\ \left \{ {{y=-2} \atop {x=3}} \right.$