52-(3у+6+у+3у):38=50

Question

52-(3у+6+у+3у):38=50

Answer 1

52-(3y+6+y+3y):38=50
52-(3y+6+4y):38=50
52-(7y+6):38=50
-(7y+6):38=50-52
-(7y+6):38=-2
-7y-6=(-2)*38
-7y-6=-76
-7y=-76+6
-7y=-70
7y=70
y=70/7
y=10

Comments

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Answer 2

52-(3y+6+y+3y):38=50
52-(7y+6):38=50
(7y+6):38=52-50=2
(7y+6)=38*2=76
7y=76-6=70
y=70:7=10