X+x/2=-12 x+x/3=8 x+x/7=-8 x+x/2=-6

Решите задачу:

$x+ \frac{x}{2} =-12 \\ \\ \frac{2x+x}{2} =-12 \\ \\ \frac{3x}{2} =-12 \\ \\ 3x=-24 \\ \\ x=-8$

$x+ \frac{x}{3} =8 \\ \\ \frac{3x+x}{3} =8 \\ \\ \frac{4x}{3} =8 \\ \\ 4x=24 \\ \\ x=6$

$x+ \frac{x}{7} =-8 \\ \\ \frac{7x+x}{7} =-8 \\ \\ \frac{8x}{7} =-8 \\ \\ 8x=-56 \\ \\ x=-7$

$x+ \frac{x}{2} =-6 \\ \\ \frac{2x+x}{2} =-6 \\ \\ \frac{3x}{2} =-6 \\ \\ 3x=-12 \\ \\ x=-4$