a) (x+27)-12=42 б)115-(35+y)=39 B)z-35-64=16 г) 28-t+35=53

Question

a) (x+27)-12=42 б)115-(35+y)=39 B)z-35-64=16 г) 28-t+35=53

Answer 1

(х+27)-12=42

х+27=42+12

х+27=54

х=54-27

х=27

115-(35+у)=39

-35-у=39-115

-35-у=-76

-у=-76+35

-у=-41

у=41

z-35-64=16

z=16+35+64

z=115

28-t+35=53

-t=53-28-35

-t=-10

t=10