Sin^4 x + cos^4 x = cos4x
(1-cos2x)²/4+(1+cos2x)²/4=cos4x 2+2cos²2x=4cos4x 2+2cos²2x=8cos²2x-4 8cos²2x-2cos2x-6=0 4cos²2x-cos2x-3=0 cos2x=a 4a²-a-3=0 D=1+48=49 a1=(1-7)/8=-3/4⇒cos2x=-3/4⇒x=+-1/2arccos3/4+2πn a2=(1+7)/8=1⇒cos2x=1⇒x=πn
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