1\\\\16x^2-1>0\\\\(4x-1)(4x+1)>0\\\\x_1=\frac{1}{4},\; x_2=\frac{-1}{4}\\\\+ + + + (-\frac{1}{4})- - - - -(\frac{1}{4})+ + + + \\\\x\in (-\infty;-\frac{1}{4})U(\frac{1}{4};+\infty)" alt="16x^2>1\\\\16x^2-1>0\\\\(4x-1)(4x+1)>0\\\\x_1=\frac{1}{4},\; x_2=\frac{-1}{4}\\\\+ + + + (-\frac{1}{4})- - - - -(\frac{1}{4})+ + + + \\\\x\in (-\infty;-\frac{1}{4})U(\frac{1}{4};+\infty)" align="absmiddle" class="latex-formula">