Решите систему : 9х^2-14х=у 9х-14=у

Решите задачу:

$\left \{ {{9x^2-14x=y} \atop {9x-14=y}} \right. \\ \\ 9x^2-9x-14x+14=0 \\ \\ 9x^2-23x+14=0 \\ \\ D=b^2-4ac=(-23)^2-4*9*14=529-504=25 \\ \\ x_{1} = \frac{-b+ \sqrt{D} }{2a} =\frac{23+5}{2*9} = \frac{28}{18}= \frac{14}{9} =1 \frac{5}{9} \\ \\ x_{2} = \frac{-b- \sqrt{D} }{2a} =\frac{23-5}{2*9} = \frac{18}{18} =1 \\ \\ y_{1}=9*\frac{14}{9}-14=0 \\ \\ y_{2}=9*1-14=-5$